What are the solutions to the equation m^2+2m=8 ?

The solutions to the equation m^2+2m=8 are m=2,m=-4

Find the zeros of m^2+2m=8

The zeros of m^2+2m=8 are m=2,m=-4

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m^{2} + 2 m = 8

m = 2, m = - 4

Solution steps

m^{2} + 2 m = 8

Move

8

to the left side

m^{2} + 2 m - 8 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 8) = 6

m_{1, 2} = \frac{- 2 \pm 6}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 2 + 6}{2 \cdot 1}, m_{2} = \frac{- 2 - 6}{2 \cdot 1}

m = \frac{- 2 + 6}{2 \cdot 1} : 2

m = \frac{- 2 - 6}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

m = 2, m = - 4

- 1 \cdot - 1

ln (e)

3 p^{2} + 16 p + 5

2 (x - 6)^{2} - 5 \geq 37

\frac{m ^{3} + 8 m ^{2} + 19 m + 12}{m + 3}

What are the solutions to the equation m^2+2m=8 ?
The solutions to the equation m^2+2m=8 are m=2,m=-4
Find the zeros of m^2+2m=8
The zeros of m^2+2m=8 are m=2,m=-4