What are the solutions to the equation 4v^2+16v=65 ?

The solutions to the equation 4v^2+16v=65 are v= 5/2 ,v=-13/2

Find the zeros of 4v^2+16v=65

The zeros of 4v^2+16v=65 are v= 5/2 ,v=-13/2

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4 v^{2} + 16 v = 65

v = \frac{5}{2}, v = - \frac{13}{2}

Decimal Notation

v = 2.5, v = - 6.5

Solution steps

4 v^{2} + 16 v = 65

Move

65

to the left side

4 v^{2} + 16 v - 65 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 4 ( - 65 )}{2 \cdot 4}

1 6^{2} - 4 \cdot 4 (- 65) = 36

v_{1, 2} = \frac{- 16 \pm 36}{2 \cdot 4}

Separate the solutions

v_{1} = \frac{- 16 + 36}{2 \cdot 4}, v_{2} = \frac{- 16 - 36}{2 \cdot 4}

v = \frac{- 16 + 36}{2 \cdot 4} : \frac{5}{2}

v = \frac{- 16 - 36}{2 \cdot 4} : - \frac{13}{2}

The solutions to the quadratic equation are:

v = \frac{5}{2}, v = - \frac{13}{2}

3 x + 9 = 5 x + 5

(x^{2} - y^{2})^{2}

2 5^{(\frac{3}{8})^{4}}

30 x^{2} - 5 x - 5

8 \cdot (- \frac{7}{2})

What are the solutions to the equation 4v^2+16v=65 ?
The solutions to the equation 4v^2+16v=65 are v= 5/2 ,v=-13/2
Find the zeros of 4v^2+16v=65
The zeros of 4v^2+16v=65 are v= 5/2 ,v=-13/2