What is simplify-3sqrt(24a^4b^2c^3) ?

The solution to simplify-3sqrt(24a^4b^2c^3) is -6sqrt(6)a^2bcsqrt(c)

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simplify-3sqrt(24a^4b^2c^3)

simplify

- 3 24 a^{4} b^{2} c^{3}

- 66 a^{2} b c c

Solution steps

- 3 24 a^{4} b^{2} c^{3}

Apply radical rule:

ab = a b,

assuming

a \geq 0, b \geq 0

24 a^{4} b^{2} c^{3} = 24 a^{4} b^{2} c^{3}

= - 324 a^{4} b^{2} c^{3}

Apply radical rule:

ab = a b,

assuming

a \geq 0, b \geq 0

a^{4} b^{2} c^{3} = a^{4} b^{2} c^{3}

= - 324 a^{4} b^{2} c^{3}

Apply radical rule:

ab = a b,

assuming

a \geq 0, b \geq 0

b^{2} c^{3} = b^{2} c^{3}

= - 324 a^{4} b^{2} c^{3}

24 = 26

= - 3 \cdot 26 a^{4} b^{2} c^{3}

Simplify

a^{4} : a^{2}

= - 3 \cdot 26 a^{2} b^{2} c^{3}

Apply radical rule:

a^{2} = a,

assuming

a \geq 0

b^{2} = b

= - 3 \cdot 26 a^{2} b c^{3}

Simplify

c^{3} : c c

= - 3 \cdot 26 a^{2} b c c

Multiply the numbers:

- 3 \cdot 2 = - 6

= - 66 a^{2} b c c

\frac{1}{25} - 16 z^{2}

3 - 2 (x - 3) = 4

- 2 x - 4 x = 1

r^{2} - 7 r + 12 = 0

π (4)^{2}

What is simplify-3sqrt(24a^4b^2c^3) ?
The solution to simplify-3sqrt(24a^4b^2c^3) is -6sqrt(6)a^2bcsqrt(c)