What are the solutions to the equation 2x^2+3=0 ?

The solutions to the equation 2x^2+3=0 are x=sqrt(3/2)i,x=-sqrt(3/2)i

Find the zeros of 2x^2+3=0

The zeros of 2x^2+3=0 are x=sqrt(3/2)i,x=-sqrt(3/2)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 3 = 0

x = \frac{3}{2} i, x = - \frac{3}{2} i

Solution steps

2 x^{2} + 3 = 0

Move

3

to the right side

2 x^{2} = - 3

Divide both sides by

2

x^{2} = - \frac{3}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{3}{2}, x = - - \frac{3}{2}

- \frac{3}{2} = \frac{3}{2} i

- - \frac{3}{2} = - \frac{3}{2} i

x = \frac{3}{2} i, x = - \frac{3}{2} i

(- 1)^{\frac{2}{5}}

9 - 4 x^{2}

x^{3} y - 25 x y

(x^{- \frac{2}{3}} y^{- \frac{1}{2}})^{2}

(8 \cdot 1 0^{4}) (9 \cdot 1 0^{- 8})

What are the solutions to the equation 2x^2+3=0 ?
The solutions to the equation 2x^2+3=0 are x=sqrt(3/2)i,x=-sqrt(3/2)i
Find the zeros of 2x^2+3=0
The zeros of 2x^2+3=0 are x=sqrt(3/2)i,x=-sqrt(3/2)i