What are the solutions to the equation 9x^2-7=18 ?

The solutions to the equation 9x^2-7=18 are x= 5/3 ,x=-5/3

Find the zeros of 9x^2-7=18

The zeros of 9x^2-7=18 are x= 5/3 ,x=-5/3

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9 x^{2} - 7 = 18

x = \frac{5}{3}, x = - \frac{5}{3}

Solution steps

9 x^{2} - 7 = 18

Move

7

to the right side

9 x^{2} = 25

Divide both sides by

9

x^{2} = \frac{25}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{25}{9}, x = - \frac{25}{9}

\frac{25}{9} = \frac{5}{3}

- \frac{25}{9} = - \frac{5}{3}

x = \frac{5}{3}, x = - \frac{5}{3}

\frac{- 9 i}{8 i}

80 y^{2} - 5 z^{2}

106 + 94 + 135 + 105

2 x^{2} - x - 10

3 (x - 1) > - 15

What are the solutions to the equation 9x^2-7=18 ?
The solutions to the equation 9x^2-7=18 are x= 5/3 ,x=-5/3
Find the zeros of 9x^2-7=18
The zeros of 9x^2-7=18 are x= 5/3 ,x=-5/3