What are the solutions to the equation (x-3)^2+4=20 ?

The solutions to the equation (x-3)^2+4=20 are x=7,x=-1

Find the zeros of (x-3)^2+4=20

The zeros of (x-3)^2+4=20 are x=7,x=-1

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(x - 3)^{2} + 4 = 20

x = 7, x = - 1

Solution steps

(x - 3)^{2} + 4 = 20

Move

4

to the right side

(x - 3)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 16 : x = 7

Solve

x - 3 = - 16 : x = - 1

The solutions to the quadratic equation are:

x = 7, x = - 1

- 3 x + 9 - 2 x = - 12 - 5 x

- \frac{8}{- 2}

6 x^{2} + 3 x + 2 = 0

p^{2} - 13 = 0

\frac{a ^{2} - 81}{a ^{2} - 9 a} \leq 0

What are the solutions to the equation (x-3)^2+4=20 ?
The solutions to the equation (x-3)^2+4=20 are x=7,x=-1
Find the zeros of (x-3)^2+4=20
The zeros of (x-3)^2+4=20 are x=7,x=-1