What are the solutions to the equation 121x^2-400=0 ?

The solutions to the equation 121x^2-400=0 are x= 20/11 ,x=-20/11

Find the zeros of 121x^2-400=0

The zeros of 121x^2-400=0 are x= 20/11 ,x=-20/11

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121 x^{2} - 400 = 0

x = \frac{20}{11}, x = - \frac{20}{11}

Solution steps

121 x^{2} - 400 = 0

Move

400

to the right side

121 x^{2} = 400

Divide both sides by

121

x^{2} = \frac{400}{121}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{400}{121}, x = - \frac{400}{121}

\frac{400}{121} = \frac{20}{11}

- \frac{400}{121} = - \frac{20}{11}

x = \frac{20}{11}, x = - \frac{20}{11}

2 r^{2} - 3 r - 1 = 0

3 x^{2} + 1 = 4 x

3 (x - 4)^{2} - 12

7 x + 14 = 9 x - 8

3 x^{3} + x^{2} - 38 x + 24

What are the solutions to the equation 121x^2-400=0 ?
The solutions to the equation 121x^2-400=0 are x= 20/11 ,x=-20/11
Find the zeros of 121x^2-400=0
The zeros of 121x^2-400=0 are x= 20/11 ,x=-20/11