What are the solutions to the equation x^2-10x-4=0 ?

The solutions to the equation x^2-10x-4=0 are x=5+sqrt(29),x=5-sqrt(29)

Find the zeros of x^2-10x-4=0

The zeros of x^2-10x-4=0 are x=5+sqrt(29),x=5-sqrt(29)

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x^{2} - 10 x - 4 = 0

x = 5 + 29, x = 5 - 29

Decimal Notation

x = 10.38516 \dots, x = - 0.38516 \dots

Solution steps

x^{2} - 10 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot (- 4) = 229

x_{1, 2} = \frac{- ( - 10 ) \pm 2 29}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 29}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2 29}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2 29}{2 \cdot 1} : 5 + 29

x = \frac{- ( - 10 ) - 2 29}{2 \cdot 1} : 5 - 29

The solutions to the quadratic equation are:

x = 5 + 29, x = 5 - 29

- (x + 1)^{2} - 4 = 0

\frac{1}{lo g _{b} ( 4 )}

3 (x^{2} - 3) + 1 = - 5

3 x - 2 = x + 1

\frac{81}{36}

What are the solutions to the equation x^2-10x-4=0 ?
The solutions to the equation x^2-10x-4=0 are x=5+sqrt(29),x=5-sqrt(29)
Find the zeros of x^2-10x-4=0
The zeros of x^2-10x-4=0 are x=5+sqrt(29),x=5-sqrt(29)