What is factor 4n^2+n-33 ?

The solution to factor 4n^2+n-33 is (4n-11)(n+3)

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factor 4n^2+n-33

factor

4 n^{2} + n - 33

(4 n - 11) (n + 3)

Solution steps

4 n^{2} + n - 33

Break the expression into groups

= (4 n^{2} - 11 n) + (12 n - 33)

Factor out

n

from

4 n^{2} - 11 n : n (4 n - 11)

Factor out

3

from

12 n - 33 : 3 (4 n - 11)

= n (4 n - 11) + 3 (4 n - 11)

Factor out common term

4 n - 11

= (4 n - 11) (n + 3)

- 2 x - 10 < 8 + 8 x

x^{2} - 4 x + 8

- 2 x - 6 > 6 x - 9

\frac{3}{7} - \frac{4}{5} - \frac{8}{9} + 3

3200 (\frac{1}{2})^{\frac{60}{14}}