What are the solutions to the equation 5x^2-12x+8=5 ?

The solutions to the equation 5x^2-12x+8=5 are x=(6+sqrt(21))/5 ,x=(6-sqrt(21))/5

Find the zeros of 5x^2-12x+8=5

The zeros of 5x^2-12x+8=5 are x=(6+sqrt(21))/5 ,x=(6-sqrt(21))/5

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5 x^{2} - 12 x + 8 = 5

x = \frac{6 + 21}{5}, x = \frac{6 - 21}{5}

Solution steps

5 x^{2} - 12 x + 8 = 5

Move

5

to the left side

5 x^{2} - 12 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 5 \cdot 3}{2 \cdot 5}

(- 12)^{2} - 4 \cdot 5 \cdot 3 = 221

x_{1, 2} = \frac{- ( - 12 ) \pm 2 21}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 21}{2 \cdot 5}, x_{2} = \frac{- ( - 12 ) - 2 21}{2 \cdot 5}

x = \frac{- ( - 12 ) + 2 21}{2 \cdot 5} : \frac{6 + 21}{5}

x = \frac{- ( - 12 ) - 2 21}{2 \cdot 5} : \frac{6 - 21}{5}

The solutions to the quadratic equation are:

x = \frac{6 + 21}{5}, x = \frac{6 - 21}{5}

3 - \frac{4 x}{5} = 2

\frac{1}{- 4 + 2 i}

29 x + 29 = 29 x - 11

\frac{x ^{2} + 8 x + 12}{x + 4} \geq 0

2 x^{3} - 7 x^{2} - 4 x

What are the solutions to the equation 5x^2-12x+8=5 ?
The solutions to the equation 5x^2-12x+8=5 are x=(6+sqrt(21))/5 ,x=(6-sqrt(21))/5
Find the zeros of 5x^2-12x+8=5
The zeros of 5x^2-12x+8=5 are x=(6+sqrt(21))/5 ,x=(6-sqrt(21))/5