What are the solutions to the equation -4x^2+12x-9=0 ?

The solutions to the equation -4x^2+12x-9=0 are x= 3/2

Find the zeros of -4x^2+12x-9=0

The zeros of -4x^2+12x-9=0 are x= 3/2

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- 4 x^{2} + 12 x - 9 = 0

x = \frac{3}{2}

Decimal Notation

x = 1.5

Solution steps

- 4 x^{2} + 12 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 4 ) ( - 9 )}{2 ( - 4 )}

1 2^{2} - 4 (- 4) (- 9) = 0

x_{1, 2} = \frac{- 12 \pm 0}{2 ( - 4 )}

x = \frac{- 12}{2 ( - 4 )}

\frac{- 12}{2 ( - 4 )} = \frac{3}{2}

x = \frac{3}{2}

The solution to the quadratic equation is:

x = \frac{3}{2}

\frac{1}{2} (- 6 w + 8) - 5 = 3 w - 1

\frac{1}{2} x^{2} = \frac{2}{5} x^{2}

(5 - 7 i) (8 + 13 i)

- \frac{3}{5} x \geq 18

8 - 6

What are the solutions to the equation -4x^2+12x-9=0 ?
The solutions to the equation -4x^2+12x-9=0 are x= 3/2
Find the zeros of -4x^2+12x-9=0
The zeros of -4x^2+12x-9=0 are x= 3/2