What are the solutions to the equation -3x^2+24x-36=0 ?

The solutions to the equation -3x^2+24x-36=0 are x=2,x=6

Find the zeros of -3x^2+24x-36=0

The zeros of -3x^2+24x-36=0 are x=2,x=6

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- 3 x^{2} + 24 x - 36 = 0

x = 2, x = 6

Solution steps

- 3 x^{2} + 24 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 ( - 3 ) ( - 36 )}{2 ( - 3 )}

2 4^{2} - 4 (- 3) (- 36) = 12

x_{1, 2} = \frac{- 24 \pm 12}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 24 + 12}{2 ( - 3 )}, x_{2} = \frac{- 24 - 12}{2 ( - 3 )}

x = \frac{- 24 + 12}{2 ( - 3 )} : 2

x = \frac{- 24 - 12}{2 ( - 3 )} : 6

The solutions to the quadratic equation are:

x = 2, x = 6

- 2 e^{- 2}

\frac{x - 1}{2} - \frac{x - 2}{3} - \frac{x - 3}{4} = \frac{x - 5}{5}

\frac{5}{6 - 9 i}

3^{2} + x^{2} = 6^{2}

x \geq 7 or x \leq 4

What are the solutions to the equation -3x^2+24x-36=0 ?
The solutions to the equation -3x^2+24x-36=0 are x=2,x=6
Find the zeros of -3x^2+24x-36=0
The zeros of -3x^2+24x-36=0 are x=2,x=6