What are the solutions to the equation 3^2+x^2=13^2 ?

The solutions to the equation 3^2+x^2=13^2 are x=4sqrt(10),x=-4sqrt(10)

Find the zeros of 3^2+x^2=13^2

The zeros of 3^2+x^2=13^2 are x=4sqrt(10),x=-4sqrt(10)

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3^{2} + x^{2} = 1 3^{2}

x = 410, x = - 410

Decimal Notation

x = 12.64911 \dots, x = - 12.64911 \dots

Solution steps

3^{2} + x^{2} = 1 3^{2}

Move

3^{2}

to the right side

x^{2} = 160

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 160, x = - 160

160 = 410

- 160 = - 410

x = 410, x = - 410

r^{2} + 3 r - 3 = 0

x^{4} + 2 x^{2} y^{2} + y^{4}

3 x + 1 = 0

(\frac{13}{3})^{2}

14 x^{2} y^{5} (11 x^{5} y^{5})

What are the solutions to the equation 3^2+x^2=13^2 ?
The solutions to the equation 3^2+x^2=13^2 are x=4sqrt(10),x=-4sqrt(10)
Find the zeros of 3^2+x^2=13^2
The zeros of 3^2+x^2=13^2 are x=4sqrt(10),x=-4sqrt(10)