simplify 8/(-2+i)

Solution

simplify

\frac{8}{- 2 + i}

- \frac{16}{5} - \frac{8}{5} i

Solution steps

\frac{8}{- 2 + i}

Multiply by the conjugate

\frac{- 2 - i}{- 2 - i}

= \frac{8 ( - 2 - i )}{( - 2 + i ) ( - 2 - i )}

Simplify

\frac{8 ( - 2 - i )}{( - 2 + i ) ( - 2 - i )} : \frac{- 16 - 8 i}{5}

= \frac{- 16 - 8 i}{5}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{- 16}{5} + \frac{- 8}{5} i

Simplify

\frac{- 16}{5} + \frac{- 8}{5} i : - \frac{16}{5} - \frac{8}{5} i

= - \frac{16}{5} - \frac{8}{5} i

- \frac{5}{4} = x - \frac{7}{10}

2 b^{2} - 5 b + 3

8 (3 x - 7) = - 6 (x + 7) + 4

x^{2} \leq 2 x + 1

\frac{100}{\frac{2}{2}} = \frac{x}{\frac{3}{2}}