What are the solutions to the equation 49x^2-42x+9=0 ?

The solutions to the equation 49x^2-42x+9=0 are x= 3/7

Find the zeros of 49x^2-42x+9=0

The zeros of 49x^2-42x+9=0 are x= 3/7

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49 x^{2} - 42 x + 9 = 0

x = \frac{3}{7}

Decimal Notation

x = 0.42857 \dots

Solution steps

49 x^{2} - 42 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 42 ) \pm ( - 42 ) ^{2} - 4 \cdot 49 \cdot 9}{2 \cdot 49}

(- 42)^{2} - 4 \cdot 49 \cdot 9 = 0

x_{1, 2} = \frac{- ( - 42 ) \pm 0}{2 \cdot 49}

x = \frac{- ( - 42 )}{2 \cdot 49}

\frac{- ( - 42 )}{2 \cdot 49} = \frac{3}{7}

x = \frac{3}{7}

The solution to the quadratic equation is:

x = \frac{3}{7}

\frac{e}{- 2} > - 3

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64 \cdot \frac{1}{4}

2 (10 - 6 x) = x - 8 x

What are the solutions to the equation 49x^2-42x+9=0 ?
The solutions to the equation 49x^2-42x+9=0 are x= 3/7
Find the zeros of 49x^2-42x+9=0
The zeros of 49x^2-42x+9=0 are x= 3/7