What are the solutions to the equation a^2-6a+2=0 ?

The solutions to the equation a^2-6a+2=0 are a=3+sqrt(7),a=3-sqrt(7)

Find the zeros of a^2-6a+2=0

The zeros of a^2-6a+2=0 are a=3+sqrt(7),a=3-sqrt(7)

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a^{2} - 6 a + 2 = 0

a = 3 + 7, a = 3 - 7

Decimal Notation

a = 5.64575 \dots, a = 0.35424 \dots

Solution steps

a^{2} - 6 a + 2 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 2 = 27

a_{1, 2} = \frac{- ( - 6 ) \pm 2 7}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 6 ) + 2 7}{2 \cdot 1}, a_{2} = \frac{- ( - 6 ) - 2 7}{2 \cdot 1}

a = \frac{- ( - 6 ) + 2 7}{2 \cdot 1} : 3 + 7

a = \frac{- ( - 6 ) - 2 7}{2 \cdot 1} : 3 - 7

The solutions to the quadratic equation are:

a = 3 + 7, a = 3 - 7

9 x^{2} + 2 = 164

12 \geq 15 - 6 y

(- 8.6)^{0}

x + \frac{3}{4} \leq 2 x - \frac{5}{4} \leq \frac{5}{2} x + 1

(\frac{- 1 + 4 x ^{\frac{2}{3}}}{4 x ^{\frac{1}{3}}})^{2}

What are the solutions to the equation a^2-6a+2=0 ?
The solutions to the equation a^2-6a+2=0 are a=3+sqrt(7),a=3-sqrt(7)
Find the zeros of a^2-6a+2=0
The zeros of a^2-6a+2=0 are a=3+sqrt(7),a=3-sqrt(7)