What are the solutions to the equation -4x^2+2x+1=0 ?

The solutions to the equation -4x^2+2x+1=0 are x=-(-1+sqrt(5))/4 ,x=(1+sqrt(5))/4

Find the zeros of -4x^2+2x+1=0

The zeros of -4x^2+2x+1=0 are x=-(-1+sqrt(5))/4 ,x=(1+sqrt(5))/4

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- 4 x^{2} + 2 x + 1 = 0

x = - \frac{- 1 + 5}{4}, x = \frac{1 + 5}{4}

Decimal Notation

x = - 0.30901 \dots, x = 0.80901 \dots

Solution steps

- 4 x^{2} + 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 4 ) \cdot 1}{2 ( - 4 )}

2^{2} - 4 (- 4) \cdot 1 = 25

x_{1, 2} = \frac{- 2 \pm 2 5}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 2 + 2 5}{2 ( - 4 )}, x_{2} = \frac{- 2 - 2 5}{2 ( - 4 )}

x = \frac{- 2 + 2 5}{2 ( - 4 )} : - \frac{- 1 + 5}{4}

x = \frac{- 2 - 2 5}{2 ( - 4 )} : \frac{1 + 5}{4}

The solutions to the quadratic equation are:

x = - \frac{- 1 + 5}{4}, x = \frac{1 + 5}{4}

\frac{( a ^{2} - b ^{2} )}{a + b} - (a + b)^{2} + 2^{2}

4 p = 1

\frac{13}{27} - (\frac{88}{135})^{2}

3 y^{2} = 6 y

x^{2} + \frac{1}{6} x - \frac{1}{2} + \frac{1}{4} = 0

What are the solutions to the equation -4x^2+2x+1=0 ?
The solutions to the equation -4x^2+2x+1=0 are x=-(-1+sqrt(5))/4 ,x=(1+sqrt(5))/4
Find the zeros of -4x^2+2x+1=0
The zeros of -4x^2+2x+1=0 are x=-(-1+sqrt(5))/4 ,x=(1+sqrt(5))/4