What are the solutions to the equation 15=8x^2-14x ?

The solutions to the equation 15=8x^2-14x are x= 5/2 ,x=-3/4

Find the zeros of 15=8x^2-14x

The zeros of 15=8x^2-14x are x= 5/2 ,x=-3/4

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15 = 8 x^{2} - 14 x

x = \frac{5}{2}, x = - \frac{3}{4}

Decimal

x = 2.5, x = - 0.75

Solution steps

15 = 8 x^{2} - 14 x

Switch sides

8 x^{2} - 14 x = 15

Move

15

to the left side

8 x^{2} - 14 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 8 ( - 15 )}{2 \cdot 8}

(- 14)^{2} - 4 \cdot 8 (- 15) = 26

x_{1, 2} = \frac{- ( - 14 ) \pm 26}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 26}{2 \cdot 8}, x_{2} = \frac{- ( - 14 ) - 26}{2 \cdot 8}

x = \frac{- ( - 14 ) + 26}{2 \cdot 8} : \frac{5}{2}

x = \frac{- ( - 14 ) - 26}{2 \cdot 8} : - \frac{3}{4}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - \frac{3}{4}

- 2 \leq \frac{2 x - 6}{6} \leq 4

x^{2} + (x + 2)^{2} = (x - 14)^{2}

- 2 x + 6 + 4 x = - 12

9 c + 4 \leq 22

\frac{25}{81}

What are the solutions to the equation 15=8x^2-14x ?
The solutions to the equation 15=8x^2-14x are x= 5/2 ,x=-3/4
Find the zeros of 15=8x^2-14x
The zeros of 15=8x^2-14x are x= 5/2 ,x=-3/4