What are the solutions to the equation y^2+6y+2=0 ?

The solutions to the equation y^2+6y+2=0 are y=-3+sqrt(7),y=-3-sqrt(7)

Find the zeros of y^2+6y+2=0

The zeros of y^2+6y+2=0 are y=-3+sqrt(7),y=-3-sqrt(7)

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y^{2} + 6 y + 2 = 0

y = - 3 + 7, y = - 3 - 7

Decimal Notation

y = - 0.35424 \dots, y = - 5.64575 \dots

Solution steps

y^{2} + 6 y + 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 2 = 27

y_{1, 2} = \frac{- 6 \pm 2 7}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 6 + 2 7}{2 \cdot 1}, y_{2} = \frac{- 6 - 2 7}{2 \cdot 1}

y = \frac{- 6 + 2 7}{2 \cdot 1} : - 3 + 7

y = \frac{- 6 - 2 7}{2 \cdot 1} : - 3 - 7

The solutions to the quadratic equation are:

y = - 3 + 7, y = - 3 - 7

x^{3} + 2 x

(\frac{x ^{2}}{4 y})^{2}

a^{2} + 7 a - 60

lo g_{3} (9) + lo g_{4} (2)

\frac{3 2 ^{10} \cdot 4 ^{9}}{16}

What are the solutions to the equation y^2+6y+2=0 ?
The solutions to the equation y^2+6y+2=0 are y=-3+sqrt(7),y=-3-sqrt(7)
Find the zeros of y^2+6y+2=0
The zeros of y^2+6y+2=0 are y=-3+sqrt(7),y=-3-sqrt(7)