What are the solutions to the equation -x^2+4x+2=0 ?

The solutions to the equation -x^2+4x+2=0 are x=2-sqrt(6),x=2+sqrt(6)

Find the zeros of -x^2+4x+2=0

The zeros of -x^2+4x+2=0 are x=2-sqrt(6),x=2+sqrt(6)

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- x^{2} + 4 x + 2 = 0

x = 2 - 6, x = 2 + 6

Decimal Notation

x = - 0.44948 \dots, x = 4.44948 \dots

Solution steps

- x^{2} + 4 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) \cdot 2}{2 ( - 1 )}

4^{2} - 4 (- 1) \cdot 2 = 26

x_{1, 2} = \frac{- 4 \pm 2 6}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 4 + 2 6}{2 ( - 1 )}, x_{2} = \frac{- 4 - 2 6}{2 ( - 1 )}

x = \frac{- 4 + 2 6}{2 ( - 1 )} : 2 - 6

x = \frac{- 4 - 2 6}{2 ( - 1 )} : 2 + 6

The solutions to the quadratic equation are:

x = 2 - 6, x = 2 + 6

\frac{x}{4} - 1 = 8

\frac{ln ( 2 )}{ln ( 1.1 )}

3 ∣ x ∣ + ∣ x - 2 ∣ \leq 6

\frac{10 !}{8 ! 2 !}

A = 4000 \cdot \frac{0.01}{1.0 1 ^{24} - 1}

What are the solutions to the equation -x^2+4x+2=0 ?
The solutions to the equation -x^2+4x+2=0 are x=2-sqrt(6),x=2+sqrt(6)
Find the zeros of -x^2+4x+2=0
The zeros of -x^2+4x+2=0 are x=2-sqrt(6),x=2+sqrt(6)