What are the solutions to the equation 200x-x^2=5x+6200 ?

The solutions to the equation 200x-x^2=5x+6200 are x=40,x=155

Find the zeros of 200x-x^2=5x+6200

The zeros of 200x-x^2=5x+6200 are x=40,x=155

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200 x - x^{2} = 5 x + 6200

x = 40, x = 155

Solution steps

200 x - x^{2} = 5 x + 6200

Move

6200

to the left side

200 x - x^{2} - 6200 = 5 x

Move

5 x

to the left side

- x^{2} + 195 x - 6200 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 195 \pm 19 5 ^{2} - 4 ( - 1 ) ( - 6200 )}{2 ( - 1 )}

19 5^{2} - 4 (- 1) (- 6200) = 115

x_{1, 2} = \frac{- 195 \pm 115}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 195 + 115}{2 ( - 1 )}, x_{2} = \frac{- 195 - 115}{2 ( - 1 )}

x = \frac{- 195 + 115}{2 ( - 1 )} : 40

x = \frac{- 195 - 115}{2 ( - 1 )} : 155

The solutions to the quadratic equation are:

x = 40, x = 155

6 x^{2} y^{5} + 15 x y^{7}

54 n^{3} + 117 n^{2} - 45 n

- 11 y + y^{2} - 152 = 0

(x - 7) (x + 4)^{2} (x - 1) \geq 0

- \frac{1}{- 3}

What are the solutions to the equation 200x-x^2=5x+6200 ?
The solutions to the equation 200x-x^2=5x+6200 are x=40,x=155
Find the zeros of 200x-x^2=5x+6200
The zeros of 200x-x^2=5x+6200 are x=40,x=155