What are the solutions to the equation -5x^2+8x-3=0 ?

The solutions to the equation -5x^2+8x-3=0 are x= 3/5 ,x=1

Find the zeros of -5x^2+8x-3=0

The zeros of -5x^2+8x-3=0 are x= 3/5 ,x=1

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- 5 x^{2} + 8 x - 3 = 0

x = \frac{3}{5}, x = 1

Decimal Notation

x = 0.6, x = 1

Solution steps

- 5 x^{2} + 8 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 5 ) ( - 3 )}{2 ( - 5 )}

8^{2} - 4 (- 5) (- 3) = 2

x_{1, 2} = \frac{- 8 \pm 2}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 8 + 2}{2 ( - 5 )}, x_{2} = \frac{- 8 - 2}{2 ( - 5 )}

x = \frac{- 8 + 2}{2 ( - 5 )} : \frac{3}{5}

x = \frac{- 8 - 2}{2 ( - 5 )} : 1

The solutions to the quadratic equation are:

x = \frac{3}{5}, x = 1

x^{2} + 24 = 14 x

9^{2} + 1 1^{2} = c^{2}

- 5 x + 2 \geq 52

- \frac{5}{3} + \frac{2}{4} - 3

n^{2} + 10 n + 24

What are the solutions to the equation -5x^2+8x-3=0 ?
The solutions to the equation -5x^2+8x-3=0 are x= 3/5 ,x=1
Find the zeros of -5x^2+8x-3=0
The zeros of -5x^2+8x-3=0 are x= 3/5 ,x=1