What are the solutions to the equation 6x^2+40x=14 ?

The solutions to the equation 6x^2+40x=14 are x= 1/3 ,x=-7

Find the zeros of 6x^2+40x=14

The zeros of 6x^2+40x=14 are x= 1/3 ,x=-7

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6 x^{2} + 40 x = 14

x = \frac{1}{3}, x = - 7

Decimal Notation

x = 0.33333 \dots, x = - 7

Solution steps

6 x^{2} + 40 x = 14

Move

14

to the left side

6 x^{2} + 40 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 6 ( - 14 )}{2 \cdot 6}

4 0^{2} - 4 \cdot 6 (- 14) = 44

x_{1, 2} = \frac{- 40 \pm 44}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 40 + 44}{2 \cdot 6}, x_{2} = \frac{- 40 - 44}{2 \cdot 6}

x = \frac{- 40 + 44}{2 \cdot 6} : \frac{1}{3}

x = \frac{- 40 - 44}{2 \cdot 6} : - 7

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - 7

15 - 5 k \geq 0

\frac{2 x + 3}{x - 2} \leq 5 x - 2

8 x + 2 > 348 x + 2 > 34

x^{2} - 25 = - x^{2} + 25

352 - 32 \cdot x = 0

What are the solutions to the equation 6x^2+40x=14 ?
The solutions to the equation 6x^2+40x=14 are x= 1/3 ,x=-7
Find the zeros of 6x^2+40x=14
The zeros of 6x^2+40x=14 are x= 1/3 ,x=-7