What are the solutions to the equation 4x^2+9x-9=0 ?

The solutions to the equation 4x^2+9x-9=0 are x= 3/4 ,x=-3

Find the zeros of 4x^2+9x-9=0

The zeros of 4x^2+9x-9=0 are x= 3/4 ,x=-3

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4 x^{2} + 9 x - 9 = 0

x = \frac{3}{4}, x = - 3

Decimal Notation

x = 0.75, x = - 3

Solution steps

4 x^{2} + 9 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 4 ( - 9 )}{2 \cdot 4}

9^{2} - 4 \cdot 4 (- 9) = 15

x_{1, 2} = \frac{- 9 \pm 15}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 9 + 15}{2 \cdot 4}, x_{2} = \frac{- 9 - 15}{2 \cdot 4}

x = \frac{- 9 + 15}{2 \cdot 4} : \frac{3}{4}

x = \frac{- 9 - 15}{2 \cdot 4} : - 3

The solutions to the quadratic equation are:

x = \frac{3}{4}, x = - 3

\frac{3 π}{2} + \frac{π}{4}

10 x^{2} - 29 x - 21

x \geq - 4 and x \leq - 1

(- \frac{1}{4} r^{5} v^{7} w^{2}) (5 r^{3} w^{8} x) (- 8 v^{5} w^{19} x^{5})

x^{2} - 12 x + 49 = 22

What are the solutions to the equation 4x^2+9x-9=0 ?
The solutions to the equation 4x^2+9x-9=0 are x= 3/4 ,x=-3
Find the zeros of 4x^2+9x-9=0
The zeros of 4x^2+9x-9=0 are x= 3/4 ,x=-3