What is factor 16y^2+8y+1 ?

The solution to factor 16y^2+8y+1 is (4y+1)^2

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factor 16y^2+8y+1

factor

16 y^{2} + 8 y + 1

(4 y + 1)^{2}

Solution steps

16 y^{2} + 8 y + 1

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

16 y^{2} = (4 y)^{2}

1 = 1^{2}

8 y = 2 \cdot 4 y \cdot 1

= (4 y)^{2} + 2 \cdot 4 y \cdot 1 + 1^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

(4 y)^{2} + 2 \cdot 4 y \cdot 1 + 1^{2} = (4 y + 1)^{2}

= (4 y + 1)^{2}

lo g_{4} (16384)

30 a^{3} x^{2} y - 60 a^{2} x^{3} y^{2} - 90 a^{2} x y

9 x^{2} - 6 x + 37 = 0

9 x - 9 = 10 x - 7

5 (x + 1) - x = 4 (x - 1) + 9