What are the solutions to the equation 1/3 y^2-8/27 =0 ?

The solutions to the equation 1/3 y^2-8/27 =0 are y=(2sqrt(2))/3 ,y=-(2sqrt(2))/3

Find the zeros of 1/3 y^2-8/27 =0

The zeros of 1/3 y^2-8/27 =0 are y=(2sqrt(2))/3 ,y=-(2sqrt(2))/3

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\frac{1}{3} y^{2} - \frac{8}{27} = 0

y = \frac{2 2}{3}, y = - \frac{2 2}{3}

Solution steps

\frac{1}{3} y^{2} - \frac{8}{27} = 0

Move

\frac{8}{27}

to the right side

\frac{1}{3} y^{2} = \frac{8}{27}

Multiply both sides by

3

y^{2} = \frac{8}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = \frac{8}{9}, y = - \frac{8}{9}

\frac{8}{9} = \frac{2 2}{3}

- \frac{8}{9} = - \frac{2 2}{3}

y = \frac{2 2}{3}, y = - \frac{2 2}{3}

x^{2} - 19 x + 18 \leq 0

y^{6} - x^{2}

2 - 2 p - 4 p^{2}

\frac{7 - 2 x}{18} - \frac{1 - 5 x}{12} > 0

2 x^{2} + 9 x = 78 - 3 x

What are the solutions to the equation 1/3 y^2-8/27 =0 ?
The solutions to the equation 1/3 y^2-8/27 =0 are y=(2sqrt(2))/3 ,y=-(2sqrt(2))/3
Find the zeros of 1/3 y^2-8/27 =0
The zeros of 1/3 y^2-8/27 =0 are y=(2sqrt(2))/3 ,y=-(2sqrt(2))/3