What are the solutions to the equation 3x^2+2x+12=0 ?

The solutions to the equation 3x^2+2x+12=0 are x=-1/3+i(sqrt(35))/3 ,x=-1/3-i(sqrt(35))/3

Find the zeros of 3x^2+2x+12=0

The zeros of 3x^2+2x+12=0 are x=-1/3+i(sqrt(35))/3 ,x=-1/3-i(sqrt(35))/3

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3 x^{2} + 2 x + 12 = 0

x = - \frac{1}{3} + i \frac{35}{3}, x = - \frac{1}{3} - i \frac{35}{3}

Solution steps

3 x^{2} + 2 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 \cdot 12}{2 \cdot 3}

Simplify

2^{2} - 4 \cdot 3 \cdot 12 : 235 i

x_{1, 2} = \frac{- 2 \pm 2 35 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 2 + 2 35 i}{2 \cdot 3}, x_{2} = \frac{- 2 - 2 35 i}{2 \cdot 3}

x = \frac{- 2 + 2 35 i}{2 \cdot 3} : - \frac{1}{3} + i \frac{35}{3}

x = \frac{- 2 - 2 35 i}{2 \cdot 3} : - \frac{1}{3} - i \frac{35}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{3} + i \frac{35}{3}, x = - \frac{1}{3} - i \frac{35}{3}

a^{2} - 5 a - 14

4 a^{4} + 6 a^{2}

lo g_{2} (16)

\frac{x}{2} \geq 5

lo g_{10} (1000000)

What are the solutions to the equation 3x^2+2x+12=0 ?
The solutions to the equation 3x^2+2x+12=0 are x=-1/3+i(sqrt(35))/3 ,x=-1/3-i(sqrt(35))/3
Find the zeros of 3x^2+2x+12=0
The zeros of 3x^2+2x+12=0 are x=-1/3+i(sqrt(35))/3 ,x=-1/3-i(sqrt(35))/3