What is 1/6 <((2x-17))/(12)<= 2/3 ?

The solution to 1/6 <((2x-17))/(12)<= 2/3 is 19/2 <x<= 25/2

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1/6 <((2x-17))/(12)<= 2/3

\frac{1}{6} < \frac{( 2 x - 17 )}{12} \leq \frac{2}{3}

\frac{19}{2} < x \leq \frac{25}{2}

Interval Notation

(\frac{19}{2}, \frac{25}{2}]

Decimal Notation

9.5 < x \leq 12.5

Solution steps

\frac{1}{6} < \frac{( 2 x - 17 )}{12} \leq \frac{2}{3}

a < u \leq b

then

a < u and u \leq b

\frac{1}{6} < \frac{( 2 x - 17 )}{12} and \frac{( 2 x - 17 )}{12} \leq \frac{2}{3}

\frac{1}{6} < \frac{2 x - 17}{12} : x > \frac{19}{2}

\frac{2 x - 17}{12} \leq \frac{2}{3} : x \leq \frac{25}{2}

Combine the intervals

x > \frac{19}{2} and x \leq \frac{25}{2}

Merge Overlapping Intervals

\frac{19}{2} < x \leq \frac{25}{2}

2 (x - 250) - 4 (3 x - 40) = 5

\frac{3}{1 - 2 i}

\frac{2}{5} x = 6

2 x^{2} - 2 x y - 4 y^{2}

(2 + 2 b)^{2} - a - 2 b

What is 1/6 <((2x-17))/(12)<= 2/3 ?
The solution to 1/6 <((2x-17))/(12)<= 2/3 is 19/2 <x<= 25/2