What is ((12x^{-2})^0)/(6x^4y^{-3)} ?

The solution to ((12x^{-2})^0)/(6x^4y^{-3)} is (y^3)/(6x^4)

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simplify ((12x^{-2})^0)/(6x^4y^{-3)}

simplify

\frac{( 12 x ^{- 2} ) ^{0}}{6 x ^{4} y ^{- 3}}

\frac{y ^{3}}{6 x ^{4}}

Solution steps

\frac{( 12 x ^{- 2} ) ^{0}}{6 x ^{4} y ^{- 3}}

Apply exponent rule:

a^{0} = 1,

assuming

a \neq = 0

(12 x^{- 2})^{0} = 1

= \frac{1}{6 x ^{4} y ^{- 3}}

Simplify

6 x^{4} y^{- 3} : \frac{6 x ^{4}}{y ^{3}}

= \frac{1}{\frac{6 x ^{4}}{y ^{3}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{y ^{3}}{6 x ^{4}}

2.18 \cdot 0.128 \cdot (x - 11) = - (8.09) (4.186) (x - 52.8)

9 x^{2} - 64 = 0

x^{4} - 4 x^{3} - x^{2} + 4 x \leq 0

3 e^{x} - 2 e^{2 x} \geq 1

\frac{x + 3}{6} = \frac{x - 6}{3}

What is ((12x^{-2})^0)/(6x^4y^{-3)} ?
The solution to ((12x^{-2})^0)/(6x^4y^{-3)} is (y^3)/(6x^4)