What are the solutions to the equation -x^2+x+1=0 ?

The solutions to the equation -x^2+x+1=0 are x=-(-1+sqrt(5))/2 ,x=(1+sqrt(5))/2

Find the zeros of -x^2+x+1=0

The zeros of -x^2+x+1=0 are x=-(-1+sqrt(5))/2 ,x=(1+sqrt(5))/2

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- x^{2} + x + 1 = 0

x = - \frac{- 1 + 5}{2}, x = \frac{1 + 5}{2}

Solution steps

- x^{2} + x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) \cdot 1}{2 ( - 1 )}

1^{2} - 4 (- 1) \cdot 1 = 5

x_{1, 2} = \frac{- 1 \pm 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 1 + 5}{2 ( - 1 )}, x_{2} = \frac{- 1 - 5}{2 ( - 1 )}

x = \frac{- 1 + 5}{2 ( - 1 )} : - \frac{- 1 + 5}{2}

x = \frac{- 1 - 5}{2 ( - 1 )} : \frac{1 + 5}{2}

The solutions to the quadratic equation are:

x = - \frac{- 1 + 5}{2}, x = \frac{1 + 5}{2}

5 q + 1 = 6 q - 79

2 x^{2} < x + 6

4 x^{2} = 4 - x

x = lo g_{3} (9)

2 (3 a^{2} - 1) - 6 a = 5 a

What are the solutions to the equation -x^2+x+1=0 ?
The solutions to the equation -x^2+x+1=0 are x=-(-1+sqrt(5))/2 ,x=(1+sqrt(5))/2
Find the zeros of -x^2+x+1=0
The zeros of -x^2+x+1=0 are x=-(-1+sqrt(5))/2 ,x=(1+sqrt(5))/2