What is (2+i)^2-(4-i)^2 ?

The solution to (2+i)^2-(4-i)^2 is -12+12i

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simplify (2+i)^2-(4-i)^2

simplify

(2 + i)^{2} - (4 - i)^{2}

- 12 + 12 i

Solution steps

(2 + i)^{2} - (4 - i)^{2}

(2 + i)^{2} = 4 i + 3

(4 - i)^{2} = - 8 i + 15

= 4 i + 3 - (- 8 i + 15)

Expand

- (- 8 i + 15) : 8 i - 15

= 4 i + 3 + 8 i - 15

Group like terms

= 4 i + 8 i + 3 - 15

Add similar elements:

4 i + 8 i = 12 i

= 12 i + 3 - 15

Subtract the numbers:

3 - 15 = - 12

= 12 i - 12

Rewrite in standard complex form:

- 12 + 12 i

= - 12 + 12 i

x - 4 \geq 1

(x - 4) (3 x + 2) = 0

4 - \frac{2}{7} w = 18

\frac{3 π}{2} + 2 π

d^{2} - 22 d + 21 = 0