What are the solutions to the equation 2x^2-6x-2=0 ?

The solutions to the equation 2x^2-6x-2=0 are x=(3+sqrt(13))/2 ,x=(3-sqrt(13))/2

Find the zeros of 2x^2-6x-2=0

The zeros of 2x^2-6x-2=0 are x=(3+sqrt(13))/2 ,x=(3-sqrt(13))/2

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2 x^{2} - 6 x - 2 = 0

x = \frac{3 + 13}{2}, x = \frac{3 - 13}{2}

Decimal Notation

x = 3.30277 \dots, x = - 0.30277 \dots

Solution steps

2 x^{2} - 6 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 ( - 2 )}{2 \cdot 2}

(- 6)^{2} - 4 \cdot 2 (- 2) = 213

x_{1, 2} = \frac{- ( - 6 ) \pm 2 13}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 13}{2 \cdot 2}, x_{2} = \frac{- ( - 6 ) - 2 13}{2 \cdot 2}

x = \frac{- ( - 6 ) + 2 13}{2 \cdot 2} : \frac{3 + 13}{2}

x = \frac{- ( - 6 ) - 2 13}{2 \cdot 2} : \frac{3 - 13}{2}

The solutions to the quadratic equation are:

x = \frac{3 + 13}{2}, x = \frac{3 - 13}{2}

(\frac{π}{6}) - 2 π

(- 3 x)^{2}

2 x^{2} + 5 = - 31

\frac{3}{( 2 ( \frac{1}{2} ) + 3 ) ^{\frac{5}{2}}}

- \frac{3}{4} x^{2} + 2 = 0

What are the solutions to the equation 2x^2-6x-2=0 ?
The solutions to the equation 2x^2-6x-2=0 are x=(3+sqrt(13))/2 ,x=(3-sqrt(13))/2
Find the zeros of 2x^2-6x-2=0
The zeros of 2x^2-6x-2=0 are x=(3+sqrt(13))/2 ,x=(3-sqrt(13))/2