What are the solutions to the equation y^2+16=0 ?

The solutions to the equation y^2+16=0 are y=4i,y=-4i

Find the zeros of y^2+16=0

The zeros of y^2+16=0 are y=4i,y=-4i

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y^{2} + 16 = 0

y = 4 i, y = - 4 i

Solution steps

y^{2} + 16 = 0

Move

16

to the right side

y^{2} = - 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - 16, y = - - 16

- 16 = 4 i

- - 16 = - 4 i

y = 4 i, y = - 4 i

\frac{- 8}{( - \frac{12}{13} )}

\frac{2 n ^{2}}{n}

\frac{1}{3} + \frac{1}{15}

\frac{5 a}{10 a}

2 x - 5 > 7

What are the solutions to the equation y^2+16=0 ?
The solutions to the equation y^2+16=0 are y=4i,y=-4i
Find the zeros of y^2+16=0
The zeros of y^2+16=0 are y=4i,y=-4i