What is 0<= x/7-2(x+3)<= 1 ?

The solution to 0<= x/7-2(x+3)<= 1 is -49/13 <= x<=-42/13

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0<= x/7-2(x+3)<= 1

0 \leq \frac{x}{7} - 2 (x + 3) \leq 1

- \frac{49}{13} \leq x \leq - \frac{42}{13}

Interval Notation

[- \frac{49}{13}, - \frac{42}{13}]

Decimal Notation

- 3.76923 \dots \leq x \leq - 3.23076 \dots

Solution steps

0 \leq \frac{x}{7} - 2 (x + 3) \leq 1

a \leq u \leq b

then

a \leq u and u \leq b

0 \leq \frac{x}{7} - 2 (x + 3) and \frac{x}{7} - 2 (x + 3) \leq 1

0 \leq \frac{x}{7} - 2 (x + 3) : x \leq - \frac{42}{13}

\frac{x}{7} - 2 (x + 3) \leq 1 : x \geq - \frac{49}{13}

Combine the intervals

x \leq - \frac{42}{13} and x \geq - \frac{49}{13}

Merge Overlapping Intervals

- \frac{49}{13} \leq x \leq - \frac{42}{13}

x^{2} = 12 x - 61

m^{2} + 18 m - 19

\frac{1}{1 !}

\frac{2}{3} x + \frac{5}{3} = - \frac{1}{3}

\frac{x ^{3}}{x ^{- 3}}

What is 0<= x/7-2(x+3)<= 1 ?
The solution to 0<= x/7-2(x+3)<= 1 is -49/13 <= x<=-42/13