What are the solutions to the equation 24w^2-48w-72=0 ?

The solutions to the equation 24w^2-48w-72=0 are w=3,w=-1

Find the zeros of 24w^2-48w-72=0

The zeros of 24w^2-48w-72=0 are w=3,w=-1

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24 w^{2} - 48 w - 72 = 0

w = 3, w = - 1

Solution steps

24 w^{2} - 48 w - 72 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 48 ) \pm ( - 48 ) ^{2} - 4 \cdot 24 ( - 72 )}{2 \cdot 24}

(- 48)^{2} - 4 \cdot 24 (- 72) = 96

w_{1, 2} = \frac{- ( - 48 ) \pm 96}{2 \cdot 24}

Separate the solutions

w_{1} = \frac{- ( - 48 ) + 96}{2 \cdot 24}, w_{2} = \frac{- ( - 48 ) - 96}{2 \cdot 24}

w = \frac{- ( - 48 ) + 96}{2 \cdot 24} : 3

w = \frac{- ( - 48 ) - 96}{2 \cdot 24} : - 1

The solutions to the quadratic equation are:

w = 3, w = - 1

∣ x + 1 ∣ \geq 1

\frac{x - 1}{- x - 5} < 0

4 x + 5 = 2 x - 11

- \frac{1}{5} \cdot 5

\frac{( 39.2 + 38.3 + 38.9 )}{3}

What are the solutions to the equation 24w^2-48w-72=0 ?
The solutions to the equation 24w^2-48w-72=0 are w=3,w=-1
Find the zeros of 24w^2-48w-72=0
The zeros of 24w^2-48w-72=0 are w=3,w=-1