What are the solutions to the equation 0=2x^2-x-1 ?

The solutions to the equation 0=2x^2-x-1 are x=1,x=-1/2

Find the zeros of 0=2x^2-x-1

The zeros of 0=2x^2-x-1 are x=1,x=-1/2

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0 = 2 x^{2} - x - 1

x = 1, x = - \frac{1}{2}

Decimal Notation

x = 1, x = - 0.5

Solution steps

0 = 2 x^{2} - x - 1

Switch sides

2 x^{2} - x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 1) = 3

x_{1, 2} = \frac{- ( - 1 ) \pm 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 3}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 3}{2 \cdot 2}

x = \frac{- ( - 1 ) + 3}{2 \cdot 2} : 1

x = \frac{- ( - 1 ) - 3}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 1, x = - \frac{1}{2}

4000 (1 + \frac{0.0061}{365})^{365 \cdot 8}

1 + 5 b = 1 + 5 b

1. 7^{2}

3 n^{2} - 16 n + 20

2 (x - 4) + 14 \leq x - 1

What are the solutions to the equation 0=2x^2-x-1 ?
The solutions to the equation 0=2x^2-x-1 are x=1,x=-1/2
Find the zeros of 0=2x^2-x-1
The zeros of 0=2x^2-x-1 are x=1,x=-1/2