What are the solutions to the equation 4x^2-9x=0 ?

The solutions to the equation 4x^2-9x=0 are x= 9/4 ,x=0

Find the zeros of 4x^2-9x=0

The zeros of 4x^2-9x=0 are x= 9/4 ,x=0

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4 x^{2} - 9 x = 0

x = \frac{9}{4}, x = 0

Decimal Notation

x = 2.25, x = 0

Solution steps

4 x^{2} - 9 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 9)^{2} - 4 \cdot 4 \cdot 0 = 9

x_{1, 2} = \frac{- ( - 9 ) \pm 9}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 9}{2 \cdot 4}, x_{2} = \frac{- ( - 9 ) - 9}{2 \cdot 4}

x = \frac{- ( - 9 ) + 9}{2 \cdot 4} : \frac{9}{4}

x = \frac{- ( - 9 ) - 9}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

x = \frac{9}{4}, x = 0

\frac{x}{3} + \frac{x}{9} - \frac{4 x}{27} = \frac{11}{27} - \frac{x}{9}

x^{2} + 16 x + 39 = 0

\frac{1}{2} x - 3 = \frac{3}{4} x + 1

14 z^{2} + 3 z - 2

\frac{π}{3}

What are the solutions to the equation 4x^2-9x=0 ?
The solutions to the equation 4x^2-9x=0 are x= 9/4 ,x=0
Find the zeros of 4x^2-9x=0
The zeros of 4x^2-9x=0 are x= 9/4 ,x=0