What are the solutions to the equation 2x^2-10x-3=0 ?

The solutions to the equation 2x^2-10x-3=0 are x=(5+sqrt(31))/2 ,x=(5-sqrt(31))/2

Find the zeros of 2x^2-10x-3=0

The zeros of 2x^2-10x-3=0 are x=(5+sqrt(31))/2 ,x=(5-sqrt(31))/2

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2 x^{2} - 10 x - 3 = 0

x = \frac{5 + 31}{2}, x = \frac{5 - 31}{2}

Decimal Notation

x = 5.28388 \dots, x = - 0.28388 \dots

Solution steps

2 x^{2} - 10 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

(- 10)^{2} - 4 \cdot 2 (- 3) = 231

x_{1, 2} = \frac{- ( - 10 ) \pm 2 31}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 31}{2 \cdot 2}, x_{2} = \frac{- ( - 10 ) - 2 31}{2 \cdot 2}

x = \frac{- ( - 10 ) + 2 31}{2 \cdot 2} : \frac{5 + 31}{2}

x = \frac{- ( - 10 ) - 2 31}{2 \cdot 2} : \frac{5 - 31}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 31}{2}, x = \frac{5 - 31}{2}

n > \frac{- 19}{5}

2 \cdot \frac{1}{15.9154900000000 \dots}

\frac{6 !}{3 !}

\frac{1}{7.8} \times \frac{12}{1} + \frac{6.8}{1}

- 39 x = - 702

What are the solutions to the equation 2x^2-10x-3=0 ?
The solutions to the equation 2x^2-10x-3=0 are x=(5+sqrt(31))/2 ,x=(5-sqrt(31))/2
Find the zeros of 2x^2-10x-3=0
The zeros of 2x^2-10x-3=0 are x=(5+sqrt(31))/2 ,x=(5-sqrt(31))/2