What are the solutions to the equation x^2+17x+16=0 ?

The solutions to the equation x^2+17x+16=0 are x=-1,x=-16

Find the zeros of x^2+17x+16=0

The zeros of x^2+17x+16=0 are x=-1,x=-16

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x^{2} + 17 x + 16 = 0

x = - 1, x = - 16

Solution steps

x^{2} + 17 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

1 7^{2} - 4 \cdot 1 \cdot 16 = 15

x_{1, 2} = \frac{- 17 \pm 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 17 + 15}{2 \cdot 1}, x_{2} = \frac{- 17 - 15}{2 \cdot 1}

x = \frac{- 17 + 15}{2 \cdot 1} : - 1

x = \frac{- 17 - 15}{2 \cdot 1} : - 16

The solutions to the quadratic equation are:

x = - 1, x = - 16

8 - 3 x \geq 7 x - 6

- 10 > x - 6 + 3 x

\frac{2}{a + 2} - \frac{3}{2 a}

7 + 5

(5 + 3)^{2}

What are the solutions to the equation x^2+17x+16=0 ?
The solutions to the equation x^2+17x+16=0 are x=-1,x=-16
Find the zeros of x^2+17x+16=0
The zeros of x^2+17x+16=0 are x=-1,x=-16