What are the solutions to the equation 4x^2-36x+93=0 ?

The solutions to the equation 4x^2-36x+93=0 are x= 9/2+sqrt(3)i,x= 9/2-sqrt(3)i

Find the zeros of 4x^2-36x+93=0

The zeros of 4x^2-36x+93=0 are x= 9/2+sqrt(3)i,x= 9/2-sqrt(3)i

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4 x^{2} - 36 x + 93 = 0

x = \frac{9}{2} + 3 i, x = \frac{9}{2} - 3 i

Solution steps

4 x^{2} - 36 x + 93 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 4 \cdot 93}{2 \cdot 4}

Simplify

(- 36)^{2} - 4 \cdot 4 \cdot 93 : 83 i

x_{1, 2} = \frac{- ( - 36 ) \pm 8 3 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 8 3 i}{2 \cdot 4}, x_{2} = \frac{- ( - 36 ) - 8 3 i}{2 \cdot 4}

x = \frac{- ( - 36 ) + 8 3 i}{2 \cdot 4} : \frac{9}{2} + 3 i

x = \frac{- ( - 36 ) - 8 3 i}{2 \cdot 4} : \frac{9}{2} - 3 i

The solutions to the quadratic equation are:

x = \frac{9}{2} + 3 i, x = \frac{9}{2} - 3 i

\frac{x}{2} + 1 = \frac{2 x}{2}

- 6 c + 12 \geq 8

(x + 1)^{2} = 7918 - 2 x

∣ 6 x - 3 ∣ < 27

3 x^{2} - 3 x - 36

What are the solutions to the equation 4x^2-36x+93=0 ?
The solutions to the equation 4x^2-36x+93=0 are x= 9/2+sqrt(3)i,x= 9/2-sqrt(3)i
Find the zeros of 4x^2-36x+93=0
The zeros of 4x^2-36x+93=0 are x= 9/2+sqrt(3)i,x= 9/2-sqrt(3)i