What is (x+4)/(x-8)>= 3 ?

The solution to (x+4)/(x-8)>= 3 is 8<x<= 14

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(x+4)/(x-8)>= 3

\frac{x + 4}{x - 8} \geq 3

8 < x \leq 14

Interval Notation

(8, 14]

Solution steps

\frac{x + 4}{x - 8} \geq 3

Rewrite in standard form

\frac{- 2 x + 28}{x - 8} \geq 0

Factor

\frac{- 2 x + 28}{x - 8} : \frac{- 2 ( x - 14 )}{x - 8}

\frac{- 2 ( x - 14 )}{x - 8} \geq 0

Multiply both sides by

- 1

(reverse the inequality)

\frac{( - 2 ( x - 14 ) ) ( - 1 )}{x - 8} \leq 0 \cdot (- 1)

Simplify

\frac{2 ( x - 14 )}{x - 8} \leq 0

Divide both sides by

2

\frac{\frac{2 ( x - 14 )}{x - 8}}{2} \leq \frac{0}{2}

Simplify

\frac{x - 14}{x - 8} \leq 0

Identify the intervals

8 < x \leq 14

4 y^{2} - 8 y - 12

(\frac{1}{64})^{\frac{1}{2}}

3 x^{3} - 12 x

45 = \frac{t ^{2} - t}{2}

(6 x^{2} + 4 x) + (4 x^{2} - 8 x)