What are the solutions to the equation 25(5x-5)^2-37=-33 ?

The solutions to the equation 25(5x-5)^2-37=-33 are x= 27/25 ,x= 23/25

Find the zeros of 25(5x-5)^2-37=-33

The zeros of 25(5x-5)^2-37=-33 are x= 27/25 ,x= 23/25

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25 (5 x - 5)^{2} - 37 = - 33

x = \frac{27}{25}, x = \frac{23}{25}

Decimal Notation

x = 1.08, x = 0.92

Solution steps

25 (5 x - 5)^{2} - 37 = - 33

Move

37

to the right side

25 (5 x - 5)^{2} = 4

Divide both sides by

25

(5 x - 5)^{2} = \frac{4}{25}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x - 5 = \frac{4}{25} : x = \frac{27}{25}

Solve

5 x - 5 = - \frac{4}{25} : x = \frac{23}{25}

The solutions to the quadratic equation are:

x = \frac{27}{25}, x = \frac{23}{25}

(\frac{1}{3})^{2}

4 x^{2} - 8 x + 12 = 9

3 n^{2} + 7 n - 20

(5 x^{2} y^{10})^{\frac{1}{5}}

∣ 1 - 4 x ∣ \geq - 11

What are the solutions to the equation 25(5x-5)^2-37=-33 ?
The solutions to the equation 25(5x-5)^2-37=-33 are x= 27/25 ,x= 23/25
Find the zeros of 25(5x-5)^2-37=-33
The zeros of 25(5x-5)^2-37=-33 are x= 27/25 ,x= 23/25