What are the solutions to the equation 72y^2=13y+15 ?

The solutions to the equation 72y^2=13y+15 are y= 5/9 ,y=-3/8

Find the zeros of 72y^2=13y+15

The zeros of 72y^2=13y+15 are y= 5/9 ,y=-3/8

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72 y^{2} = 13 y + 15

y = \frac{5}{9}, y = - \frac{3}{8}

Decimal Notation

y = 0.55555 \dots, y = - 0.375

Solution steps

72 y^{2} = 13 y + 15

Move

15

to the left side

72 y^{2} - 15 = 13 y

Move

13 y

to the left side

72 y^{2} - 15 - 13 y = 0

Write in the standard form

a x^{2} + b x + c = 0

72 y^{2} - 13 y - 15 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 72 ( - 15 )}{2 \cdot 72}

(- 13)^{2} - 4 \cdot 72 (- 15) = 67

y_{1, 2} = \frac{- ( - 13 ) \pm 67}{2 \cdot 72}

Separate the solutions

y_{1} = \frac{- ( - 13 ) + 67}{2 \cdot 72}, y_{2} = \frac{- ( - 13 ) - 67}{2 \cdot 72}

y = \frac{- ( - 13 ) + 67}{2 \cdot 72} : \frac{5}{9}

y = \frac{- ( - 13 ) - 67}{2 \cdot 72} : - \frac{3}{8}

The solutions to the quadratic equation are:

y = \frac{5}{9}, y = - \frac{3}{8}

6 \cdot \frac{π}{180}

6 + 2 y + 3 x^{2} + x^{2} y

\frac{- 16 w ^{7} r ^{2}}{- 4 w r}

90 + 0.15 x < 110 + 0.1 x

\frac{20 j ^{6}}{4 ( j ^{5} ) ^{2}}

What are the solutions to the equation 72y^2=13y+15 ?
The solutions to the equation 72y^2=13y+15 are y= 5/9 ,y=-3/8
Find the zeros of 72y^2=13y+15
The zeros of 72y^2=13y+15 are y= 5/9 ,y=-3/8