What is the answer to ((3x-1))/4+1=((x-2))/5+((x-1))/2 ?

The answer to ((3x-1))/4+1=((x-2))/5+((x-1))/2 is x=-33

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((3x-1))/4+1=((x-2))/5+((x-1))/2

\frac{( 3 x - 1 )}{4} + 1 = \frac{( x - 2 )}{5} + \frac{( x - 1 )}{2}

x = - 33

Solution steps

\frac{( 3 x - 1 )}{4} + 1 = \frac{( x - 2 )}{5} + \frac{( x - 1 )}{2}

\frac{3 x - 1}{4} + 1 = \frac{x - 2}{5} + \frac{x - 1}{2}

Multiply by LCM

5 (3 x - 1) + 20 = 4 (x - 2) + 10 (x - 1)

Expand

5 (3 x - 1) + 20 : 15 x + 15

Expand

4 (x - 2) + 10 (x - 1) : 14 x - 18

15 x + 15 = 14 x - 18

Move

15

to the right side

15 x = 14 x - 33

Move

14 x

to the left side

x = - 33

1 - \frac{1}{25}

ln (x - 2) > 0

2 \cdot ((1 + 0.02)^{\frac{1}{2 ^{- 1}}})

x^{2} + 9 x + 20 \geq 0

9 y^{2} = 30 y - 25

What is the answer to ((3x-1))/4+1=((x-2))/5+((x-1))/2 ?
The answer to ((3x-1))/4+1=((x-2))/5+((x-1))/2 is x=-33
Solve for x: ((3x-1))/4+1=((x-2))/5+((x-1))/2
The solution is x=-33