What are the solutions to the equation 2x^2+9=4x ?

The solutions to the equation 2x^2+9=4x are x=1+isqrt(7/2),x=1-isqrt(7/2)

Find the zeros of 2x^2+9=4x

The zeros of 2x^2+9=4x are x=1+isqrt(7/2),x=1-isqrt(7/2)

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2 x^{2} + 9 = 4 x

x = 1 + i \frac{7}{2}, x = 1 - i \frac{7}{2}

Solution steps

2 x^{2} + 9 = 4 x

Move

4 x

to the left side

2 x^{2} + 9 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 4 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 \cdot 9}{2 \cdot 2}

Simplify

(- 4)^{2} - 4 \cdot 2 \cdot 9 : 214 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 14 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 14 i}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 2 14 i}{2 \cdot 2}

x = \frac{- ( - 4 ) + 2 14 i}{2 \cdot 2} : 1 + i \frac{7}{2}

x = \frac{- ( - 4 ) - 2 14 i}{2 \cdot 2} : 1 - i \frac{7}{2}

The solutions to the quadratic equation are:

x = 1 + i \frac{7}{2}, x = 1 - i \frac{7}{2}

x^{3} + 3 x^{2} - 10 x

\frac{3}{8} + \frac{a}{2}

- 3 \geq x

x^{2} = 9 - 4 x

- \frac{3}{4} + \frac{7}{2}

What are the solutions to the equation 2x^2+9=4x ?
The solutions to the equation 2x^2+9=4x are x=1+isqrt(7/2),x=1-isqrt(7/2)
Find the zeros of 2x^2+9=4x
The zeros of 2x^2+9=4x are x=1+isqrt(7/2),x=1-isqrt(7/2)