What are the solutions to the equation 7q^2-28=0 ?

The solutions to the equation 7q^2-28=0 are q=2,q=-2

Find the zeros of 7q^2-28=0

The zeros of 7q^2-28=0 are q=2,q=-2

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7 q^{2} - 28 = 0

q = 2, q = - 2

Solution steps

7 q^{2} - 28 = 0

Move

28

to the right side

7 q^{2} = 28

Divide both sides by

7

q^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

q = 4, q = - 4

4 = 2

- 4 = - 2

q = 2, q = - 2

8 a^{4} - 2 a + 12 a^{3}

8 m^{2} + 12 m + 8

9 x^{6} - 4 y^{2}

- 42 > - 7 c

\frac{2}{3} + \frac{2}{3}

What are the solutions to the equation 7q^2-28=0 ?
The solutions to the equation 7q^2-28=0 are q=2,q=-2
Find the zeros of 7q^2-28=0
The zeros of 7q^2-28=0 are q=2,q=-2