What are the solutions to the equation 3z^2+4z+3=0 ?

The solutions to the equation 3z^2+4z+3=0 are z=-2/3+i(sqrt(5))/3 ,z=-2/3-i(sqrt(5))/3

Find the zeros of 3z^2+4z+3=0

The zeros of 3z^2+4z+3=0 are z=-2/3+i(sqrt(5))/3 ,z=-2/3-i(sqrt(5))/3

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3 z^{2} + 4 z + 3 = 0

z = - \frac{2}{3} + i \frac{5}{3}, z = - \frac{2}{3} - i \frac{5}{3}

Solution steps

3 z^{2} + 4 z + 3 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 \cdot 3}{2 \cdot 3}

Simplify

4^{2} - 4 \cdot 3 \cdot 3 : 25 i

z_{1, 2} = \frac{- 4 \pm 2 5 i}{2 \cdot 3}

Separate the solutions

z_{1} = \frac{- 4 + 2 5 i}{2 \cdot 3}, z_{2} = \frac{- 4 - 2 5 i}{2 \cdot 3}

z = \frac{- 4 + 2 5 i}{2 \cdot 3} : - \frac{2}{3} + i \frac{5}{3}

z = \frac{- 4 - 2 5 i}{2 \cdot 3} : - \frac{2}{3} - i \frac{5}{3}

The solutions to the quadratic equation are:

z = - \frac{2}{3} + i \frac{5}{3}, z = - \frac{2}{3} - i \frac{5}{3}

\frac{18 x - 1}{5 x - 1} \leq 4

0.2 (d - 6) = 0.3 d + 5 - 3 + 0.1 d

x^{2} - 3 x - 10 > x - 2

2 x^{3} + 14 x^{2} - 72

0.5 x^{2} + 1 \leq 4 ∣ x ∣

What are the solutions to the equation 3z^2+4z+3=0 ?
The solutions to the equation 3z^2+4z+3=0 are z=-2/3+i(sqrt(5))/3 ,z=-2/3-i(sqrt(5))/3
Find the zeros of 3z^2+4z+3=0
The zeros of 3z^2+4z+3=0 are z=-2/3+i(sqrt(5))/3 ,z=-2/3-i(sqrt(5))/3