What is (-5x^2y^3z^4)/(15x^4y^2z^4) ?

The solution to (-5x^2y^3z^4)/(15x^4y^2z^4) is -y/(3x^2)

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simplify (-5x^2y^3z^4)/(15x^4y^2z^4)

simplify

\frac{- 5 x ^{2} y ^{3} z ^{4}}{15 x ^{4} y ^{2} z ^{4}}

- \frac{y}{3 x ^{2}}

Solution steps

\frac{- 5 x ^{2} y ^{3} z ^{4}}{15 x ^{4} y ^{2} z ^{4}}

Cancel the common factor:

z^{4}

= \frac{- 5 x ^{2} y ^{3}}{15 x ^{4} y ^{2}}

Factor the number:

15 = 5 \cdot 3

= \frac{- 5 x ^{2} y ^{3}}{5 \cdot 3 x ^{4} y ^{2}}

Cancel the common factor:

5

= \frac{- x ^{2} y ^{3}}{3 x ^{4} y ^{2}}

Simplify

\frac{y ^{3}}{y ^{2}} : y

= \frac{- x ^{2} y}{3 x ^{4}}

Simplify

\frac{x ^{2}}{x ^{4}} : \frac{1}{x ^{2}}

= \frac{- y}{3 x ^{2}}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{y}{3 x ^{2}}

x - 3 x + 2 \leq 0

24 3^{- \frac{2}{5}}

- ∣ - 7 ∣

(1 - i)^{2}

- 6 x^{2} - x + 2 = 0

What is (-5x^2y^3z^4)/(15x^4y^2z^4) ?
The solution to (-5x^2y^3z^4)/(15x^4y^2z^4) is -y/(3x^2)