What are the solutions to the equation 3y^2-15y=0 ?

The solutions to the equation 3y^2-15y=0 are y=5,y=0

Find the zeros of 3y^2-15y=0

The zeros of 3y^2-15y=0 are y=5,y=0

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3 y^{2} - 15 y = 0

y = 5, y = 0

Solution steps

3 y^{2} - 15 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

(- 15)^{2} - 4 \cdot 3 \cdot 0 = 15

y_{1, 2} = \frac{- ( - 15 ) \pm 15}{2 \cdot 3}

Separate the solutions

y_{1} = \frac{- ( - 15 ) + 15}{2 \cdot 3}, y_{2} = \frac{- ( - 15 ) - 15}{2 \cdot 3}

y = \frac{- ( - 15 ) + 15}{2 \cdot 3} : 5

y = \frac{- ( - 15 ) - 15}{2 \cdot 3} : 0

The solutions to the quadratic equation are:

y = 5, y = 0

∣ x ∣ = 9

2 (x - 1) + 4 x = 3 (x - 1) + 7

(x - 5)^{2} = 5

- \frac{9}{15}

What are the solutions to the equation 3y^2-15y=0 ?
The solutions to the equation 3y^2-15y=0 are y=5,y=0
Find the zeros of 3y^2-15y=0
The zeros of 3y^2-15y=0 are y=5,y=0