What are the solutions to the equation 8x^2-9=-8x ?

The solutions to the equation 8x^2-9=-8x are x=(-2+sqrt(22))/4 ,x=-(2+sqrt(22))/4

Find the zeros of 8x^2-9=-8x

The zeros of 8x^2-9=-8x are x=(-2+sqrt(22))/4 ,x=-(2+sqrt(22))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8 x^{2} - 9 = - 8 x

x = \frac{- 2 + 22}{4}, x = - \frac{2 + 22}{4}

Decimal Notation

x = 0.67260 \dots, x = - 1.67260 \dots

Solution steps

8 x^{2} - 9 = - 8 x

Move

8 x

to the left side

8 x^{2} - 9 + 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

8 x^{2} + 8 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 8 ( - 9 )}{2 \cdot 8}

8^{2} - 4 \cdot 8 (- 9) = 422

x_{1, 2} = \frac{- 8 \pm 4 22}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 8 + 4 22}{2 \cdot 8}, x_{2} = \frac{- 8 - 4 22}{2 \cdot 8}

x = \frac{- 8 + 4 22}{2 \cdot 8} : \frac{- 2 + 22}{4}

x = \frac{- 8 - 4 22}{2 \cdot 8} : - \frac{2 + 22}{4}

The solutions to the quadratic equation are:

x = \frac{- 2 + 22}{4}, x = - \frac{2 + 22}{4}

- \frac{9}{n ^{3}} (\frac{( n ( n + 1 ) ( 2 n + 1 ) )}{6}) - 24

3 x^{2} - 10 x

x^{3} - 3 x^{2} - 25 x - 21

x^{2} - 6 x - 1 = 0

8 = a 2

What are the solutions to the equation 8x^2-9=-8x ?
The solutions to the equation 8x^2-9=-8x are x=(-2+sqrt(22))/4 ,x=-(2+sqrt(22))/4
Find the zeros of 8x^2-9=-8x
The zeros of 8x^2-9=-8x are x=(-2+sqrt(22))/4 ,x=-(2+sqrt(22))/4